Kingston vs. George Town: Detailed 2026 Cost of Living & Quality Comparison

The minimum number of coins needed to make change for a given amount \(n\) using denominations [1, 3, 4, 5, 6] can be found using dynamic programming. The solution involves computing the minimum coins for each amount from 1 to \(n\) by considering each coin denomination and updating the minimum coins required.

Here is a Python function that implements this approach:

def min_coins(n):
if n == 0:
return 0
coins = [1, 3, 4, 5, 6]
dp = [float('inf')] * (n + 1)
dp[0] = 0
for i in range(1, n + 1):
for coin in coins:
if i >= coin:
dp[i] = min(dp[i], dp[i coin] + 1)
return dp[n]

To use this function, provide a specific value for \(n\). For example: For \(n = 10\), the minimum number of coins is 2. For \(n = 13\), the minimum number of coins is 3.

If you specify a particular \(n\), I can compute the minimum number of coins for you.